Kevin Melanio 12-23-10 skittles Experiment The purposes of this essay is to learn ab aside the exponential function exploitation and decay. Exponential growth and decay is repeated multiplication. This experiment shows how a cc skittles in a kinfolk office groundwork be exponential decay as you shake it and sway the 4 sections that is marked with an x. confront grime | Number of Skittles | Percentage of # of skittles | 0 | 200 | 0.61 | 1 | 122 | 0.63 | 2 | 77 | 0.69 | 3 | 53 | 0.58 | 4 | 31 | 0.52 | 5 | 16 | 0.06 | 6 | 1 | 0 | 7 | 0 | 0 | Average: .38 I got this add together by adding the division and dual-lane by the total phone upshot of stage. The average share should be a quarter of degree centigrade portion. The reason that the percent is way off we didnt sho ok it right on and the lines that divided the plate is not equal to each other. Stage Number | Number of Skittles | Percentage of # of skittles | 0 | 20 | 1.45 | 1 | 29 | 1.62 | 2 | 47 | 1.43 | 3 | 67 | 1.39 | 4 | 93 | 1.39 | 5 | 129 | 1.33 | 6 | 172 | 1.
16 | 7 | 200 | 0 | Average: 1.39 I got this soma by adding the percentage and divided by the total number of stage. Uo =200 Uo = 20 n ? 1 n ? 1 Un=Un-1 x .38 Un =Un-1 x 1.39 200 is commencement cheer and .38 is the 20 is t! he jump value and 1.39 is the uniform and thats how many constant and thats how many I took it out everytime I shook it. I took it out everytime I shook it. Y= 200 x .38^x Y= 20 x 1.38^x 200 is the starting value and x 20 is the starting value and x is the stage is the stage number. .38 is how number. 1.38 is the number of how many candies I took it out.candies I added. Experiment I Experiment II Y=a x b^x Y=a x b^x a=315.2579296 a=22.19081766 b=.4746048684 b=1.40187329...If you want to get a full essay, order it on our website: BestEssayCheap.com
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